The mux then sets one of its four outputs high, depending on what the counter is. In your case, you have a two bit counter (because 1 bit isn't enough to count up to 2) which is connected to the "select" part of the multiplexer. As you said, a multiplexer is an electrical switch: if I have \$n\$ "selector" inputs, I can choose from \$2^n\$ outputs. ![]() Nope! The multiplexer is the select digit part of the circuit. Is the multiplexer represented in the schematic where it says "buffers"? I'll try to cover the parts of your question separately. I guess it has to do with the low-voltage process, but it does take away the open drain's most interesting feature.
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